ATP - Sydney International 2006 (hard)
01 Jan 1970 03:00 Qialification final
Arnaud
Clement
Clement
-
Nathan
Healey
Healey
France
Australia
ATP: 0
H:
H:
2:0
ATP: 0
H:
H:
6:2, 6:2
Finished
- View
- Odds
Head to heads
| 08.01.06 | H | Clement | 2:0 | Healey |
Last matches
- Clement
- Healey
| 18.06.12 | de Schepper | Clement | L 1:2 |
| 06.07.11 | Isner | Clement | L 0:2 |
| 05.07.11 | Clement | Harrison | W 2:0 |
| 21.06.11 | Kubot | Clement | L 2:3 |
| 13.06.11 | Baghdatis | Clement | L 0:2 |
| 11.07.07 | Qureshi | Healey | L 1:2 |
| 10.07.07 | Healey | Levine | W 2:0 |
| 09.07.07 | Levine | Healey | L 0:2 |
| 21.06.07 | Roger-Vasselin | Healey | L 2:3 |
| 19.06.07 | Healey | Mello | W 2:0 |
| 1 | 2 |
|---|
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