ATP - Sydney International 2006 (hard)
01 Jan 1970 03:00 Qialification final
Arnaud
Clement
Clement
-
Nathan
Healey
Healey
France
Australia
ATP: 0
H:
H:
2:0
ATP: 0
H:
H:
6:2, 6:2
Finished
- View
- Odds
Head to heads
| 08.01.06 | H | Clement | 2:0 | Healey |
Last matches
- Clement
- Healey
| 18.06.12 | de Schepper | Clement | L 1:2 |
| 31.05.12 | Goffin | Clement | L 2:3 |
| 28.05.12 | Clement | Bogomolov Jr. |
W
3:2 ret. |
| 23.03.12 | Raonic | Clement | L 0:2 |
| 21.03.12 | Clement | Sela | W 2:0 |
| 30.07.07 | Hernych | Healey |
L
1:1 ret. |
| 11.07.07 | Qureshi | Healey | L 1:2 |
| 10.07.07 | Healey | Levine | W 2:0 |
| 09.07.07 | Levine | Healey | L 0:2 |
| 21.06.07 | Roger-Vasselin | Healey | L 2:3 |
| 1 | 2 |
|---|
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